The last question is the following: But why is it that the electrophilic bromination of phenol gives trisubstitution. The radical monobromination of bicyclo [2.2.1] heptane could give , and.
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My professor noted that bromination with light and methylene chloride gives you exclusively the monobromination product. Although the right ring is deactivated under the right condition (at higher temperatures) you can end up with more than. Monobromination is not guaranteed experimentally.
I am getting 7 products,.
Thus, it is very likely that we can selectively stop the reaction after monobromination. However , and , are unstable.on observing , planar radical at bridgehead is unstable due to angular. Indicate the major and minor products. However, bromination without light will give you the.
The given answer is 6, but why can't it be 7? I tried working it out. For the following bromination of.
